calculer la capacité d'un condensateur
2. On peut calculer la capacité d'un condensateur d'après
C=epsilon S/e
avec epsilon est la permittivité du diélectrique
Dans la capsule vidéo on a demandé de vérifier 2 fois la valeur de C. Ecrire votre calcul dans "comments" en bas de la page
1) Q/U=(0.21×10^(-12))/0,700
ReplyDelete=3×10^(-13)
=0.30×10×10^(-13)
=0,30×10^(-12)F
=0,30pF
2) 1°fois:C=epison×S/=(100×10^(-6))÷(36pi×10^(9)×2×10^(-3))
=4,4×10^(-13)F
=0,44×10^(-12)
=0,44pF
2° C=epison×S/e
=250×10^(-6)/(36pi×10^(9)×2×10^(-3))
=1,1×10^(-12)F
=1,1pF
Gaêlle Tabet
C'est Clara Abi Rached
ReplyDelete1) C=Q/U
C=0,21×10^(-12)/0,700
=3×10^(-13) F
=0,30×10^(-12) F
=0,30 pF
2) C=epsilon S/e
Epsilon= 1/36π×10^(9)
Première vérification :
C=epsilon × 100×10^(-6)/2×10^(-3)
=4,4×10^(-13) F
=0,44×10^(-12) F
=0,44 pF : vérifié
Deuxième vérification :
C=epsilon × 250×10^(-6)/2×10^(-3)
=1,11×10^(-12) F
=1,11 pF : vérifié
1) C=Q/U
ReplyDelete=0,21×10^-12/0,700
=3×10^-13
=0,30×10×10^-13
=0,30×10^-12 F
=0,30 pF
2) epsilon=1/36π×10^9
★ C=epsilon S/e
=100×10^-6/36π×10^9×2×10^-3
=4,4×10^(-13)F
=0,44×10^(-12)F
=0,44pF : vérifié
★ C=epsilon S/e
=250×10^-6/36π×10^9×2×10^-3
=1,1×10^-12F
=1,11pF : vérifié
~Rachelle Achkar
1-) C=Q/U
ReplyDelete=(0.21×10^-12)/0.700
=3×10^-13 F
=0.30 pF
2-) C=epsilon × S/e
=(1/36pi×10^9)×(100×10^-6)/2×10^-3
=4.4×10^-13 F
=0.44 pF : vérifié
C=epsilon × S/e
=(1/36pi×10^9)×(250×10^-6)/2×10^-3
=1.1×10^-12 F
=0.11 pF :vérifié
CHARBEL KHOUEIRY
ReplyDelete1)C=Q/U
C=0,21x10^(-12)/0,700
=3x10^(-13)F
=0,30x10^(-12)F
=0,30pF
2)C=epsilonxS/e
=(1/36pix10^(9))x(100x10^(-6))/2x10^-3
=4,4x10^-13F
=0,44pF:vérifié
C=epsilonxS/e
=(1/36pix10^9)x(250x10^-6)/2x10^-3
=1,1x10^-12F
=0,11pF:vérifié
1) C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2)•C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF (vérifié)
Rebecca Checrallah
1)C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2)•C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF (vérifié)
Yara El Houssein
ReplyDelete1)C=Q/U
=(0.21×10^-12)/0.700
=3×10^-13
=0.3×10^-12
=0.3pF ✔
2) ► C=εS/e
=(1/36╥×10^9)×100.10^-6/2.10^-3
=4.420×10^-13
=0.44×10^-12
=0.44pF ✔
►C=εS/e
=(1/36╥10^9)×(250×10^-6/2×10^-3)
=1.105×10^-12
=1.1pF ✔
1) C= Q/U = 0.21 x 10**(-12) / 0.700 = 3x 10**(-13) F => 3x10**(-13)/ 10**(-12) = 0,3 = 0.30pF.
ReplyDelete2) C=ℇoS/e :
2.1) C = 1 x 100x10**(-6) / (36⫪ x 10**9)(2x10**(-3)) = 4,4 x10**(-13) F => 4.4 x 10**(-13) / 10**(-12) = 0.44 pF
2.2) C' = 1x250**(-6) / (36⫪x10**9)(2x10**(-3)) ≈ 1.11x10**(-12)F = 1.11 pF.
"yassmine feir."
Andrea Akiki
ReplyDelete1) C=Q/U
=(0.21x10^(-12))/0.700
=3x10^(-13)
=0.3x10^(-12)F
=0.30 pF (Vérifié)
2)♪C=εx(S/e)
=εx{(100x10^(-6))/(2x10^(-3))}
=4.42x10^(-13)
=0.44x10^(-12) F
0.44 pF (Vérifié)
♪C'=εx(S/e)
=εx{(250x10^(-6))/(2x10^(-3))}
=1.1x10^(-12) F
=1.1 pF (Vérifié)
Rawad Geagea
ReplyDelete1)C=Q/U
C=0,21x10^(-12)/0,700
=3x10^(-13)F
=0,30x10^(-12)F
=0,30pF
2)C=epsilonxS/e
=(1/36pix10^(9))x(100x10^(-6))/2x10^-3
=4,4x10^-13F
=0,44pF:vérifié
C=epsilonxS/e
=(1/36pix10^9)x(250x10^-6)/2x10^-3
=1,1x10^-12F
=0,11pF:vérifié
1) C = Q / U
ReplyDelete= (0.21 × 10 ^ -12) /0.7
= 3 × 10 ^ -13
= 0.3 × 10 ^ -12 F
= 0.3 pF verifieè
2) • C = ep× s / e
= ( 100 × 10 ^ -6) / 36 × 10 ^ 9 × 2 × 10 ^ -3)
= 4.4 × 10 ^ -13
= 0.443× 10 ^ -12 Farad
= 0.443 pF verifiè
• C = ep×s / e
= (250 × 10 ^ -6) / (36pi × 10 ^9 × 2 × 10 ^ -3)
= 1.1 × 10 ^-12 Farad
= 1.1 pF verifieè
1]C=Q/U
ReplyDelete=(0X21X10^-12)/0.7
=3.10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2]•C= epsilon s/e
= (100×10^-6)/(36piX10^9X2X10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36piX10^9X2X10^-3)
= 1.1×10^-12 F
= 1.1 pF ((vérifié))
-GEORGIO CHAHWAN
This comment has been removed by the author.
ReplyDelete
ReplyDelete1. C=Q/U= (0,21.10^-12)/0,7= 3.10^-13 F= 0,3 pF✅
2. C=epsilon s/e= (100.10^-6)/(36pi.10^9.2.10^-3)= 4,4.10^-13 F= 0,44 pF✅
C=epsilon s/e= (250.10^-6)/(36pi.10^9.2.10^-3)= 1,1.10^-12 F= 1,1 pF✅
1) C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
= 3×10^-13
= 0.3×10^-12 F
= 0.3pF:verifieè
2)1°)C=epsilon×s/e
=1/(36pi×10^9)×(100×10^_6)/2×10^_3
=4.420970641×10^_13
=0.44×10^_12 F
=0.44 pF :vérifié
2°) C=epsilon×s/e
=1/(36pi×10^9)×(250×10^_6)/2×10^_3
=1.10524266×10^_12
=1.1 pF :vérifié
Perla kassis
1 C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2)•C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF (vérifié)
Maroun baakliny
1) C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF vérifié
2)* C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF vérifié
* C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF vérifié
Sola Sarkis
1) c=q/u
ReplyDelete=(0.21x10^-12)/0.700
=3x10^-13 F
=0.30 pF
2) C=epsilonx S/e
=(1/36pix10^9)x(100x10^-6)/2x10^-3
=4.4x10^-13 F
=0.44 pF :verife
C=epsilon × S/e
=(1/36pi×10^9)×(250×10^-6)/2×10^-3
=1.1×10^-12 F
=0.11pF :verifie
Krystibelle Machriky
1-C=Q/U
ReplyDeleteC=0,21*10^(-12)/0,700
=3*10^(-13) F
=0,30*10^(-12) F
=0,30 pF
2- 1ére vérification:
C=epsilon*S/e
=(1/36pi*10^9)*(100810^-6)/2*10^-3
=4.4*10^-13 F
=0.44 pF : vérifier
2éme vérification:
C=epsilon*S/e
=(1/36pi*10^9)*(250*10^-6)/2*10^-3
=1.1*10^-12 F
=0.11 pF: vérifier
Angelo Klaiany
1) C=Q/U
ReplyDelete=(0.21×10*-¹²)/0.700
=3×10*-¹³
=0.3×10*-¹²F
=0.3 pF (v)
2)C= epsilon×s/e
= (100×10*-6)/(36pi×10*9×2×10*-³)
= 4.4×10*-¹³
= 0.44×10*-¹² F
= 0.44 pF (v)
C= epsilon×s/e
= (250×10*-6)/(36pi×10*9×2×10*-³)
= 1.1×10*-¹² F
= 1.1 pF (v)
~karen melhem
1- C=Q/U
ReplyDelete=(0.21×10*-¹²)/0.700
=3×10*-¹³
=0.3×10*-¹²F
=0.3 pF (correct c'est verifié)
2- C= epsilon×s/e
= (100×10*-6)/(36pi×10*9×2×10*-³)
= 4.4×10*-¹³
= 0.44×10*-¹² F
= 0.44 pF (correct c'est verifié)
C= epsilon×s/e
= (250×10*-6)/(36pi×10*9×2×10*-³)
= 1.1×10*-¹² F
= 1.1 pF (correct c'est verifié)
chamiram salameh
1. C=Q/U =(0.21*10'-12)/0.7
ReplyDelete=0.3*10'-12F
=0.3pF
2.a) C= epsilon e/s
=(100×10'6)/(36pi×10'9*2×10'-3)
=0.44×10'-12pF
=0.44 F
b) C= epsilon e/s
=(250×10'6)/(36pi×10'9*2×10'-3)
=1.1×10'-12pF
=1.1F
Miraslava chemaly
1) C=Q/U
ReplyDeleteC=0,21×10^(-12)/0,700
=3×10^(-13) F
=0,30×10^(-12) F
=0,30 pF
2) C=epsilon S/e
Epsilon= 1/36π×10^(9)
Première vérification :
C=epsilon × 100×10^(-6)/2×10^(-3)
=4,4×10^(-13) F
=0,44×10^(-12) F
=0,44 pF : vérifié
Deuxième vérification :
C=epsilon × 250×10^(-6)/2×10^(-3)
=1,11×10^(-12) F
=1,11 pF : vérifié
Gabriel Mina
1)C=Q/U
ReplyDelete=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2)•C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF (vérifié)
Tracy fahed
C=Q/U
ReplyDelete=(0.21×10^-12)/0.700
=3×10^-13 F
=0.30 pF
2-) C=epsilon × S/e
=(1/36pi×10^9)×(100×10^-6)/2×10^-3
=4.4×10^-13 F
=0.44 pF : vérifié
C=epsilon × S/e
=(1/36pi×10^9)×(250×10^-6)/2×10^-3
=1.1×10^-12 F
=0.11 pF :vérifié
1) C=Q/U
ReplyDelete=(0.21×10^-13F
=0.30pF
2)C=epsilon×S/e
=(1/36pi×10^9)×(100×10^-6)/2×10^-3
=4.4×10^-13F
=0.44 pF alora c'est verifie
C=epsilon×S/e
=(1/36pi×10^9)×(250×10^-6)/2×10^-3
=1.1×10^-12F
=0.11 pF alos c'est verifie
1)C=Q/U
ReplyDeleteC=0,21x10^(-12)/0,700
=3x10^(-13)F
=0,30x10^(-12)F
=0,30pF
2)C=epsilonxS/e
=(1/36pix10^(9))x(100x10^(-6))/2x10^-3
=4,4x10^-13F
=0,44pF:verifie
C=epsilonxS/e
=(1/36pix10^9)x(250x10^-6)/2x10^-3
=1,1x10^-12F
=0,11pF:verifie
1)C=Q/U
ReplyDeleteC=0,21x10^(-12)/0,700
=3x10^(-13)F
=0,30x10^(-12)F
=0,30pF
2)C=epsilonxS/e
=(1/36pix10^(9))x(100x10^(-6))/2x10^-3
=4,4x10^-13F
=0,44pF:vérifié
C=epsilonxS/e
=(1/36pix10^9)x(250x10^-6)/2x10^-3
=1,1x10^-12F
=0,11pf
~~~~joe boulos~~~~
Charbel Moukawam
ReplyDelete1)C=Q/U
C=0,21x10*(-12)/0,700
=3x10*(-13)F
=0.30pF
2)C=epsilonxS/E
=(1/36pix10*(9))x(100x10*(-6))/2x10*-3
=4,4x10*-13F
=0,44pF:verifie
C=epsilinxS/e
=1,1x10*-12F
=0,11pF
Jennifer Rahme
ReplyDelete1-)C=Q/U
=(0.21×10^-12)/0.7
=3×10^-13
=0.3×10^-12 F
=0.3 pF (vérifié)
2-)•C= epsilon s/e
= (100×10^-6)/(36pi×10^9×2×10^-3)
= 4.4×10^-13
= 0.44×10^-12 F
= 0.44 pF (vérifié)
•C= epsilon s/e
= (250×10^-6)/(36pi×10^9×2×10^-3)
= 1.1×10^-12 F
= 1.1 pF (vérifié)
1-) C=Q/U
ReplyDelete=(0.21×10^-12)/0.700
=3×10^-13 F
=0.30 pF
2-) C=epsilon × S/e
=(1/36pi×10^9)×(100×10^-6)/2×10^-3
=4.4×10^-13 F
=0.44 pF : verifie
C=epsilon × S/e
=(1/36pi×10^9)×(250×10^-6)/2×10^-3
=1.1×10^-12 F
=0.11 pF :verifie
charbel dib
Delete